Monday, 9 May 2011

Oracle Interview based Queries - part2

51) Display the name of the employee who earns highest salary.

SQL>select ename from emp where sal=(select max(sal) from emp);

52) Display the employee number and name for employee working as clerk and earning highest salary among clerks.

SQL>select empno,ename from emp where where job='CLERK' and sal=(select max(sal) from emp where job='CLERK');

53) Display the names of salesman who earns a salary more than the highest salary of any clerk.

SQL>select ename,sal from emp where job='SALESMAN' and sal>(select max(sal) from emp where job='CLERK');

54) Display the names of clerks who earn a salary more than the lowest salary of any salesman.

SQL>select ename from emp where job='CLERK' and sal>(select min(sal) from emp where job='SALESMAN');

Display the names of employees who earn a salary more than that of Jones or that of salary grether than that of scott.

SQL>select ename,sal from emp where sal>(select sal from emp where ename='JONES')and sal> (select sal from emp where ename='SCOTT');

55) Display the names of the employees who earn highest salary in their respective departments.

SQL>select ename,sal,deptno from emp where sal in(select max(sal) from emp group by deptno);

56) Display the names of the employees who earn highest salaries in their respective job groups.

SQL>select ename,sal,job from emp where sal in(select max(sal) from emp

group by job)

57) Display the employee names who are working in accounting department.

SQL>select ename from emp where deptno=(select deptno from dept where dname='ACCOUNTING')

58) Display the employee names who are working in Chicago.

SQL>select ename from emp where deptno=(select deptno from dept where LOC='CHICAGO')

59) Display the Job groups having total salary greater than the maximum salary for managers.

SQL>SELECT JOB,SUM(SAL) FROM EMP GROUP BY JOB HAVING SUM(SAL)>(SELECT MAX(SAL) FROM EMP WHERE JOB='MANAGER');

60) Display the names of employees from department number 10 with salary greater than that of any employee working in other department.

SQL>select ename from emp where deptno=10 and sal>any(select sal from emp where deptno not in 10).

61) Display the names of the employees from department number 10 with salary greater than that of all employee working in other departments.

SQL>select ename from emp where deptno=10 and sal>all(select sal from emp where deptno not in 10).

62) Display the names of the employees in Uppercase.

SQL>select upper(ename)from emp

63) Display the names of the employees in Lower case.

SQL>select lower(ename)from emp

64) Display the names of the employees in Proper case.

SQL>select initcap(ename)from emp;

65) Display the length of Your name using appropriate function.

SQL>select length('name') from dual

66) Display the length of all the employee names.

SQL>select length(ename) from emp;

67) select name of the employee concatenate with employee number.

SQL>select ename||empno from emp;

68) User appropriate function and extract 3 characters starting from 2 characters from the following string 'Oracle'. i.e the out put should be 'ac'.

SQL>select substr('oracle',3,2) from dual

69) Find the First occurance of character 'a' from the following string i.e 'Computer Maintenance Corporation'.

SQL>SELECT INSTR('Computer Maintenance Corporation','a',1) FROM DUAL

70) Replace every occurance of alphabhet A with B in the string Allens(use translate function)

SQL>select translate('Allens','A','B') from dual

71) Display the informaction from emp table.Where job manager is found it should be displayed as boos(Use replace function).

SQL>select replace(JOB,'MANAGER','BOSS') FROM EMP;

72) Display empno,ename,deptno from emp table.Instead of display department numbers display the related department name(Use decode function).

SQL>select empno,ename,decode(deptno,10,'ACCOUNTING',20,'RESEARCH',30,'SALES',40,'OPRATIONS') from emp;

73) Display your age in days.

SQL>select to_date(sysdate)-to_date('10-sep-77')from dual

74) Display your age in months.

SQL>select months_between(sysdate,'10-sep-77') from dual

75) Display the current date as 15th August Friday Nineteen Ninety Seven.

SQL>select to_char(sysdate,'ddth Month day year') from dual

76) Display the following output for each row from emp table.scott has joined the company on Wednesday 13th August nineteen ninety.

SQL>select ENAME||' HAS JOINED THE COMPANY ON '||to_char(HIREDATE,'day ddth Month year') from EMP;

77) Find the date for nearest saturday after current date.

SQL>SELECT NEXT_DAY(SYSDATE,'SATURDAY')FROM DUAL;

78) Display current time.

SQL>select to_char(sysdate,'hh:MM:ss') from dual.

79) Display the date three months Before the current date.

SQL>select add_months(sysdate,3) from dual;

80) Display the common jobs from department number 10 and 20.

SQL>select job from emp where deptno=10 and job in(select job from emp

where deptno=20);

81) Display the jobs found in department 10 and 20 Eliminate duplicate jobs.

SQL>select distinct(job) from emp where deptno=10 or deptno=20

(or)

SQL>select distinct(job) from emp where deptno in(10,20);

82) Display the jobs which are unique to department 10.

SQL>select distinct(job) from emp where deptno=10

83) Display the details of those who do not have any person working under them.

SQL>select e.ename from emp,emp e where emp.mgr=e.empno group by e.ename having count(*)=1;

84) Display the details of those employees who are in sales department and grade is 3.

SQL>select * from emp where deptno=(select deptno from dept where dname='SALES')and sal between(select losal from salgrade where grade=3)and (select hisal from salgrade where grade=3);

85) Display those who are not managers and who are managers any one.

i)display the managers names

SQL>select distinct(m.ename) from emp e,emp m where m.empno=e.mgr;

ii)display the who are not managers

SQL>select ename from emp where ename not in(select distinct(m.ename) from emp e,emp m where m.empno=e.mgr);

86) Display those employee whose name contains not less than 4 characters.

SQL>select ename from emp where length(ename)>4;

87) Display those department whose name start with "S" while the location name ends with "K".

SQL>select dname from dept where dname like 'S%' and loc like '%K';

88) Display those employees whose manager name is JONES.

SQL>select p.ename from emp e,emp p where e.empno=p.mgr and e.ename='JONES';

89) Display those employees whose salary is more than 3000 after giving 20% increment.

SQL>select ename,sal from emp where (sal+sal*.2)>3000;

90) Display all employees while their dept names;

SQL>select ename,dname from emp,dept where emp.deptno=dept.deptno

91) Display ename who are working in sales dept.

SQL>select ename from emp where deptno=(select deptno from dept where dname='SALES');

92) Display employee name,deptname,salary and comm for those sal in between 2000 to 5000 while location is chicago.

SQL>select ename,dname,sal,comm from emp,dept where sal between 2000 and 5000 and loc='CHICAGO' and emp.deptno=dept.deptno;

93)Display those employees whose salary greter than his manager salary.

SQL>select p.ename from emp e,emp p where e.empno=p.mgr and p.sal>e.sal

94) Display those employees who are working in the same dept where his manager is work.

SQL>select p.ename from emp e,emp p where e.empno=p.mgr and p.deptno=e.deptno;

95) Display those employees who are not working under any manager.

SQL>select ename from emp where mgr is null

96) Display grade and employees name for the dept no 10 or 30 but grade is not 4 while joined the company before 31-dec-82.

SQL>select ename,grade from emp,salgrade where sal between losal and hisal and deptno in(10,30) and grade<>4 and hiredate<'31-DEC-82';

97) Update the salary of each employee by 10% increment who are not eligible for commission.

SQL>update emp set sal=sal+sal*10/100 where comm is null;

98) SELECT those employee who joined the company before 31-dec-82 while their dept location is newyork or Chicago.

SQL>SELECT EMPNO,ENAME,HIREDATE,DNAME,LOC FROM EMP,DEPTWHERE (EMP.DEPTNO=DEPT.DEPTNO)AND HIREDATE <'31-DEC-82' AND DEPT.LOC IN('CHICAGO','NEW YORK');

99) DISPLAY EMPLOYEE NAME,JOB,DEPARTMENT,LOCATION FOR ALL WHO ARE WORKING AS MANAGER?

SQL>select ename,JOB,DNAME,LOCATION from emp,DEPT where mgr is not null;

100) DISPLAY THOSE EMPLOYEES WHOSE MANAGER NAME IS JONES? --[AND ALSO DISPLAY THEIR MANAGER NAME]?

SQL> SELECT P.ENAME FROM EMP E, EMP P WHERE E.EMPNO=P.MGR AND E.ENAME='JONES';

15 comments :

  1. Hi,

    Please clear me out if am wrong on based on two of your questions (55 & 56):

    Consider there are three depts with max sal as:
    A = 100
    B = 200
    C = 300

    consider dept B has two employees one with sal 200 and another with 100.

    There by the based on your query both will be picked instead of employee with highest sal in the dept as 100 is part of the max(sal) too.

    So i feel a co-related subquery is required here. Correct me if am wrong.

    Regards,
    Cp

    ReplyDelete
  2. query to display dname,loc,ename and mgr of second highest salary employee

    ReplyDelete
    Replies
    1. SELECT D.DNAME, D.LOC, E.ENAME, E.MGR FROM EMP E, DEPT D WHERE E.DEPTNP = D.DEPTNO AND SAL = (SELECT MAX (SAL) FROM EMP WHERE SAL < (SELECT MAX (SAL) FROM EMP));

      Delete
  3. Thanks for Posting Job in Delhi, I have also post some Job Openings In India

    ReplyDelete
  4. display department wise total salary of all emp whose name start with s and end with t and having sal b/w the range of 1000 and 3000

    ReplyDelete
  5. query to display ename who is getting same salaries
    with his dname

    ReplyDelete
  6. query to display ename who is getting same salaries
    with his dname

    ReplyDelete
  7. declare
    emp_no number;
    b_sal number;
    hra number;
    da number;
    pf number;
    n_sal number;
    begin
    select sal,empno
    into b_sal,emp_no
    from emp
    where emp_n0=7788;
    dbms_output.put_line('basic salary is :' ||b_sal);
    hra:=(b_sal/100)*15;
    dbms_output.put_line('hra is :' ||hra);
    da:=(b_sal/100)*8;
    dbms_output.put_line('da is :' ||da);
    pf:=(b_sal/100)*12;
    dbms_output.put_line('pf :' ||pf);
    n_sal:=b_sal+hra+da-pf;
    dbms_output.put_line('net salary is:' ||n_sal);
    end;
    WHAT IS WRONG IN THIS CODE??

    ReplyDelete
  8. 99 QUES ANS IS---- SELECT X.*,Y.*,Z.* FROM EMP X,EMP Y,DEPT Z WHERE X.MGR=Y.EMPNO AND Y.DEPTNO=Z.DEPTNO;

    ReplyDelete
  9. Display, Your Age, Total No. of Employees and Total No. of Departments in a single query.
    how can i get these records through single sql query?

    ReplyDelete
  10. Display, Your Age, Total No. of Employees and Total No. of Departments in a single query.?

    ReplyDelete
    Replies
    1. select (select count(*) from emp)NOE ,(select count(*) from dept)NOD,round(months_between(sysdate,to_date('27-jul-1988','dd-mon-yyyy'))/12) AGE from dual;
      /

      Delete
  11. select age,( select count(empno) from emp a where a.empno=c.empno),(select count(deptno) from emp b where b.empno=c.empno) from emp c ;

    ReplyDelete