Monday 9 May 2011

Oracle Interview Based Queries-3

101) Display name and salary of ford if his salary is equal to hisal of his grade.

a)select ename,sal,grade from emp,salgrade where sal between losal and hisal and ename ='FORD' AND HISAL=SAL;

102) Display employee name,job,depart name ,manager name,his grade and make out an under department wise?

SQL>SELECT E.ENAME,E.JOB,DNAME,EMP.ENAME,GRADE FROM EMP,EMP E,SALGRADE,DEPT WHERE EMP.SAL BETWEEN LOSAL AND HISAL AND EMP.EMPNO=E.MGR AND EMP.DEPTNO=DEPT.DEPTNO ORDER BY DNAME

103) List out all employees name,job,salary,grade and depart name for every one in the company except 'CLERK'.Sort on salary display the highest salary?

SQL>SELECT ENAME,JOB,DNAME,SAL,GRADE FROM EMP,SALGRADE,DEPT WHERE SAL BETWEEN LOSAL AND HISAL AND EMP.DEPTNO=DEPT.DEPTNO AND JOB NOT IN('CLERK')ORDER BY SAL ASC;

104) Display the employee name,job and his manager.Display also employee who are without manager?

SQL>select e.ename,e.job,eMP.ename AS Manager from emp,emp e where emp.empno(+)=e.mgr

105) Find out the top 5 earners of company?

SQL>SELECT DISTINCT SAL FROM EMP E WHERE 5>=(SELECT COUNT(DISTINCT SAL) FROM EMP A WHERE A.SAL>=E.SAL)ORDER BY SAL DESC;

106) Display name of those employee who are getting the highest salary?

SQL>select ename from emp where sal=(select max(sal) from emp);

107) Display those employee whose salary is equal to average of maximum and minimum?

SQL>select ename from emp where sal=(select max(sal)+min(sal)/2 from emp);

108) Select count of employee in each department where count greater than 3?

SQL>select count(*) from emp group by deptno having count(deptno)>3

109) Display dname where at least 3 are working and display only department name?

SQL>select distinct d.dname from dept d,emp e where d.deptno=e.deptno and 3>any (select count(deptno) from emp group by deptno)

110) Display name of those managers name whose salary is more than average salary of his company?

SQL>SELECT E.ENAME,EMP.ENAME FROM EMP,EMP E WHERE EMP.EMPNO=E.MGR AND E.SAL>(SELECT AVG(SAL) FROM EMP);

111)Display those managers name whose salary is more than average salary of his employee?

SQL>SELECT DISTINCT EMP.ENAME FROM EMP,EMP E WHERE E.SAL <(SELECT AVG(EMP.SAL) FROM EMP WHERE EMP.EMPNO=E.MGR GROUP BY EMP.ENAME) AND EMP.EMPNO=E.MGR;

112) Display employee name,sal,comm and net pay for those employee whose net pay is greter than or equal to any other employee salary of the company?

SQL>select ename,sal,comm,sal+nvl(comm,0) as NetPay from emp where sal+nvl(comm,0) >any (select sal from emp)

113) Display all employees names with total sal of company with each employee name?

SQL>SELECT ENAME,(SELECT SUM(SAL) FROM EMP) FROM EMP;

114) Find out last 5(least)earners of the company.?

SQL>SELECT DISTINCT SAL FROM EMP E WHERE 5>=(SELECT COUNT(DISTINCT SAL) FROM EMP A WHERE A.SAL<=E.SAL) ORDER BY SAL DESC;

115) Find out the number of employees whose salary is greater than their manager salary?

SQL>SELECT E.ENAME FROM EMP ,EMP E WHERE EMP.EMPNO=E.MGR AND EMP.SAL<E.SAL;

116) Display those department where no employee working?

SQL>select dname from emp,dept where emp.deptno not in(emp.deptno)

117) Display those employee whose salary is ODD value?

SQL>select * from emp where sal<0;

118) Display those employee whose salary contains at least 3 digits?

SQL>select * from emp where length(sal)>=3;

119) Display those employee who joined in the company in the month of Dec?

SQL>select ename from emp where to_char(hiredate,'MON')='DEC';

120) Display those employees whose name contains "A"?

SQL>select ename from emp where instr(ename,'A')>0;

or

SQL>select ename from emp where ename like('%A%');

121) Display those employee whose deptno is available in salary?

SQL>select emp.ename from emp, emp e where emp.sal=e.deptno;

122) Display those employee whose first 2 characters from hiredate -last 2 characters of salary?

SQL>select ename,SUBSTR(hiredate,1,2)||ENAME||substr(sal,-2,2) from emp

123) Display those employee whose 10% of salary is equal to the year of joining?

SQL>select ename from emp where to_char(hiredate,'YY')=sal*0.1;

124) Display those employee who are working in sales or research?

SQL>SELECT ENAME FROM EMP WHERE DEPTNO IN(SELECT DEPTNO FROM DEPT WHERE DNAME IN('SALES','RESEARCH'));

125) Display the grade of jones?

SQL>SELECT ENAME,GRADE FROM EMP,SALGRADE WHERE SAL BETWEEN LOSAL AND HISAL AND Ename='JONES';

126) Display those employees who joined the company before 15 of the month?

select ename from emp where to_char(hiredate,'DD')<15;

127) Display those employee who has joined before 15th of the month.

a)select ename from emp where to_char(hiredate,'DD')<15;

128) Delete those records where no of employees in a particular department is less than 3.

SQL>delete from emp where deptno=(select deptno from emp group by deptno having count(deptno)<3);

129) Display the name of the department where no employee working.

SQL> SELECT E.ENAME,E.JOB,M.ENAME,M.JOB FROM EMP E,EMP M WHERE E.MGR=M.EMPNO

130) Display those employees who are working as manager.

SQL>SELECT M.ENAME MANAGER FROM EMP M ,EMP E WHERE E.MGR=M.EMPNO GROUP BY M.ENAME

131) Display those employees whose grade is equal to any number of sal but not equal to first number of sal?

SQL> SELECT ENAME,GRADE FROM EMP,SALGRADE WHERE GRADE NOT IN(SELECT SUBSTR(SAL,0,1)FROM EMP)

132) Print the details of all the employees who are Sub-ordinate to BLAKE?

SQL>select emp.ename from emp, emp e where emp.mgr=e.empno and e.ename='BLAKE';

133) Display employee name and his salary whose salary is greater than highest average of department number?

SQL>SELECT SAL FROM EMP WHERE SAL>(SELECT MAX(AVG(SAL)) FROM EMP GROUP BY DEPTNO);

134) Display the 10th record of emp table(without using rowid)

SQL>SELECT * FROM EMP WHERE ROWNUM<11

MINUS

SELECT * FROM EMP WHERE ROWNUM<10

135) Display the half of the ename's in upper case and remaining lowercase?

SQL>SELECT  SUBSTR(LOWER(ENAME),1,3)||SUBSTR(UPPER(ENAME),3,LENGTH(ENAME)) FROM EMP;

136) Display the 10th record of emp table without using group by and rowid?

SQL>SELECT * FROM EMP WHERE ROWNUM<11

MINUS

SELECT * FROM EMP WHERE ROWNUM<10

Delete the 10th record of emp table.

SQL>DELETE FROM EMP WHERE EMPNO=(SELECT EMPNO FROM EMP WHERE ROWNUM<11 MINUS SELECT EMPNO FROM EMP WHERE ROWNUM<10)

137) Create a copy of emp table;

SQL>create table new_table as select * from emp where 1=2;

138) Select ename if ename exists more than once.

SQL>select ename from emp e group by ename having count(*)>1;

139) Display all enames in reverse order?(SMITH:HTIMS).

SQL>SELECT REVERSE(ENAME)FROM EMP;

140) Display those employee whose joining of month and grade is equal.

SQL>SELECT ENAME FROM EMP WHERE SAL BETWEEN (SELECT LOSAL FROM SALGRADE WHERE GRADE=TO_CHAR(HIREDATE,'MM')) AND (SELECT HISAL FROM SALGRADE WHERE GRADE=TO_CHAR(HIREDATE,'MM'));

141) Display those employee whose joining DATE is available in deptno.

SQL>SELECT ENAME FROM EMP WHERE TO_CHAR(HIREDATE,'DD')=DEPTNO

142) Display those employees name as follows

A ALLEN

B BLAKE

SQL> SELECT SUBSTR(ENAME,1,1),ENAME FROM EMP;

143) List out the employees ename,sal,PF(20% OF SAL) from emp;

SQL>SELECT ENAME,SAL,SAL*.2 AS PF FROM EMP;

144) Create table emp with only one column empno;

SQL>Create table emp as select empno from emp where 1=2;

145) Add this column to emp table ename varchar2(20).

SQL>alter table emp add(ename varchar2(20));

146) Oops I forgot give the primary key constraint. Add in now.

SQL>alter table emp add primary key(empno);

147) Now increase the length of ename column to 30 characters.

SQL>alter table emp modify(ename varchar2(30));

148) Add salary column to emp table.

SQL>alter table emp add(sal number(10));

149) I want to give a validation saying that salary cannot be greater 10,000 (note give a name to this constraint)

SQL>alter table emp add constraint chk_001 check(sal<=10000)

150) For the time being I have decided that I will not impose this validation.My boss has agreed to pay more than 10,000.

SQL>again alter the table or drop constraint with alter table emp drop constraint chk_001 (or)Disable the constraint by using alter table emp modify constraint chk_001 disable;

25 comments :

  1. Replies
    1. Anonymous4:45 am

      List all employees that have a salary that contains the digit 5.

      Delete
    2. SELECT * FROM EMP WHERE SAL LIKE '%5%';

      Delete
    3. SELECT * FROM EMP WHERE LENGTH(SAL)=5; OR SELECT * FROM EMP WHERE SAL LIKE'_____';

      Delete
  2. List first 50% of chars of Ename in Lower Case and remaining are upper Case. CONFIRM ?PLEASE

    ReplyDelete
  3. select upper(substr('abcdef',1,length('abcdef')/2))||lower(substr('abcdef',(length('abcdef')/2)+1)) from dual;
    =ABCdef

    ReplyDelete
  4. Display employee names whose job is equal to ford job?

    ReplyDelete
    Replies
    1. SQL> select ename from emp where job=(select job from emp where ename='FORD');

      AND IF YOU WANT TO OMIT FORD THEN

      SQL> select ename from emp where job=(select job from emp where ename='FORD') and ename not in('FORD');

      Delete
  5. LIST EMPLOYEE NAMES WHO JOINED IN LAST WEEK OF THE MONTH

    ReplyDelete
    Replies
    1. SELECT ENAME,HIREDATE FROM EMP WHERE TO_CHAR(HIREDATE,'W') IN(4,5) ;

      Delete
    2. Madam I unable to understand this query, please explain meaning of in(4,5)

      Delete
    3. BRO IN EVERY MONTH WILL CONTAINS 4 SUNDAYS, 4 MONDAYS ---4SATURDAYS, BUT FEW DAYS WILL BE 5DAYS, IT MAYBE A SUNDAY OR MONDAY---. SO WITHIN A MONTH LAST WEEK WILL BE ANY DAY. THAT DAY WILL BE 4TH OR 5TH DAY, THATS WHY MADAM TAKEN 4,5. NOW I HOPE YOU UNDERSTOOD

      Delete
  6. 105 solution is wrong you have to use rank because if among 5 employee if 3 employee salary is same then.....how could you leave him....

    SQL> select * from (select ename,sal,dense_rank()over(order by sal desc)rank from emp) where rank<6;

    ReplyDelete
    Replies
    1. SELECT E.ENAME,E.SAL FROM EMP E WHERE 5 >= (SELECT COUNT(DISTINCT SAL) FROM EMP E2 WHERE E2.SAL >= E.SAL) ORDER BY SAL DESC;

      Delete
    2. HI MADAM,
      131) Display those employees whose grade is equal to any number of sal but not equal to first number of sal?

      PLEASE EXPLAIN GIVE A SOLUTION

      Delete
  7. your solution no 117 is wrong...use this

    SQL> select * from emp where mod(sal,2)>0;

    ReplyDelete
  8. your q131 solution is wrong...

    SQL> select e.ename,s.grade,e.sal,s.losal,s.hisal from emp e,salgrade s where e.sal between s.losal and s.hisal and s.gr
    ade<>substr(sal,0,1);

    ReplyDelete
  9. Please answer this question : list all the department name that are having at least one employee init?

    ReplyDelete
    Replies
    1. SELECT D.DEPTNO,DNAME,V.CNT FROM DEPT D,(SELECT COUNT(*) CNT,DEPTNO
      FROM EMP GROUP BY DEPTNO HAVING COUNT(*) > = 1) V WHERE D.DEPTNO = V.DEPTNO

      Delete
  10. 109)SELECT DNAME,MGR,V.CNT FROM DEPT D,(SELECT COUNT(*) CNT,DEPTNO FROM EMP GROUP BY DEPTNO HAVING COUNT(*) > 3) V WHERE D.DEPTNO = V.DEPTNO ;

    ReplyDelete
  11. 129)SELECT DEPTNO,DNAME FROM DEPT WHERE DEPTNO NOT IN (SELECT DEPTNO FROM EMP);

    ReplyDelete
  12. 140)SELECT * FROM EMP WHERE TO_CHAR(HIREDATE,'MM')= (SELECT GRADE FROM SALGRADE WHERE EMP.SAL BETWEEN LOSAL AND HISAL);

    ReplyDelete
  13. List the details of the emps in asc order of the Deptnos and desc of Jobs.

    ReplyDelete
  14. 104) Display the employee name,job and his manager.Display also employee who are without manager?

    FRIENDS PLEASE EXPLAIN AND GIVE A SOLUTION TO guru1214@live.com

    ReplyDelete